08-14-2012 04:13 AM
>1. 0x600000010d5518a8: 0x0000000000000000 0x600000010f2c3728
0x600000010d5518b8: 0x0000000000000440< 0x000000000f0fff00
0x600000010d5518c8: 0x0000000000000000 0x0000000000000000
[Prabhakar] What I understood by your explanation is 0x0000000000000440 this previous block address is not correct.
Yes. Or the heap address was already freed then reallocated or or bad heap address.
>2. You have to set a watchpoint and run the program
>[Prabhakar] This should be done run time or can be run using core file?
Watchpoints and breakpoints require moving the PC.