Spearman's rank correlation test (HP 48gII) (355 Views)
Posts: 16
Registered: ‎05-02-2013
Message 1 of 4 (355 Views)

# Spearman's rank correlation test (HP 48gII)

Hi. I'm given a sample and I write the rank of each number as follows:

The first row is the sample and the second row are the ranks for each number in the position i .

Now I need to calculate this value:

where n is know (in my example is 14).  It seems pretty complicated to make this computation with lists... do you know any fast way?

Thanks!

Honored Contributor
Posts: 2,392
Registered: ‎02-09-2009
Message 2 of 4 (331 Views)

# Re: Spearman's rank correlation test (HP 48gII)

[ Edited ]

Hi!, HE28:

Note: You can use the eqaution with d2.

Posts: 16
Registered: ‎05-02-2013
Message 3 of 4 (324 Views)

# Re: Spearman's rank correlation test (HP 48gII)

[ Edited ]

Is D2 the sample? If you could clarify and expand a lot more what you did in the calculator and what the variables are then I would really appreciete it because I didn't understand too much.

Edit: I'm working with one-sample test and not with two as your link suggests.

Edi2: I don't know why you're using solve equation. I have all the data I need for a numerical result.

Edit3: I think I found a way looking at the guide you sent. I create a list RANKs (in the order of the sample) and a list IND of indexes. Then I substract the index list to the RANKs one and finally I square the obtained list. After that I use the function to sum the elements of the list and that's what I put in the numerator in the formula. Is this right?

Thanks

Honored Contributor
Posts: 2,392
Registered: ‎02-09-2009
Message 4 of 4 (299 Views)

# Re: Spearman's rank correlation test (HP 48gII)

Hi!, HE28:

If you see the two pages of the next site, you can learn how use Spearman's rank correlation. Is very easy.

The opinions expressed above are the personal opinions of the authors, not of HP. By using this site, you accept the Terms of Use and Rules of Participation.